Come selezionare un cliente specifico?

Question

creo le seguenti tabelle:

create table customers (
     ID  varchar(9), 
     name varchar(15), 
     CONSTRAINT pk_id PRIMARY KEY (ID) 
); 

create table living_places (
     code varchar(7), 
     ID  varchar(9), 
     CONSTRAINT pk_code PRIMARY KEY (code) 
); 

create table policies (
     code_policy   varchar(7), 
     code_living_place varchar(7), 
     CONSTRAINT pk_code_policy PRIMARY KEY (code_policy) 
); 

create table bills (
     code   varchar(7), 
     code_policy varchar(7), 
     paid_out  boolean, 
     CONSTRAINT pk_code_bill PRIMARY KEY (code) 
); 

ho inserito le seguenti date:

insert into customers(ID, name) values('fx1','Louis'); 
insert into customers(ID, name) values('fx2','Peter'); 
insert into customers(ID, name) values('fx3','Alice'); 

insert into living_places(code, ID) values('001','fx1'); 
insert into living_places(code, ID) values('002','fx2'); 
insert into living_places(code, ID) values('003','fx1'); 
insert into living_places(code, ID) values('004','fx3'); 

insert into policies(code_policy, code_living_place) values('p1','001'); 
insert into policies(code_policy, code_living_place) values('p2','002'); 
insert into policies(code_policy, code_living_place) values('p3','003'); 

insert into bills(code, code_policy, paid_out) values('b1','p1','1'); 
insert into bills(code, code_policy, paid_out) values('b2','p1','1'); 
insert into bills(code, code_policy, paid_out) values('b3','p2','0'); 
insert into bills(code, code_policy, paid_out) values('b4','p2','1'); 
insert into bills(code, code_policy, paid_out) values('b5','p3','0'); 
insert into bills(code, code_policy, paid_out) values('b6','p3','1'); 

La domanda è: come selezionare quelle persone che hanno tutte le loro politiche a pagamento?

Il mio problema è che Louis ha due politiche p1 e p3. Politica p1 è pagato ma non lo è p3.

La mia domanda:

select ID from living_places where code in (
select code from living_places where code in (
select code_living_place from policies where code_policy in (
select code_policy from bills where paid_out=1 and code_policy not in (
select code_policy from bills where paid_out=0)))); 

MySQL me tornare:

+------+ 
| ID | 
+------+ 
| fx1 | 
+------+ 

P.S: Louis non hanno tutte le politiche pagati. Ad esempio, la bolletta b5 non viene pagata.

Answer 1

Penso che dovrebbe essere questo:

select name 
from customers 
where id not in ( 
    select iving_places.id 
    from living_places 
    inner join policies on policies.code_living_place = living_places.code 
    inner join bills on (bills.code_policy = policies.code and bills.paid_out=0) 
); 

Answer 2

Vuoi dire questo?

select c.ID from customers c 
    join living_places l 
    on l.ID = c.ID 
    join policies p 
    on p.code_living_place = l.code 
    join bills b 
    on b.code_policy = p.code_policy 
where paid_out = 0 
group by c.ID 

Answer 3

I take it you want customer who have policies paid out i.e paid_out=1? 
If yes, this following should do: 

select c.ID, c.name 
from customers c, living_places l, policies p 
where c.ID = l.ID 
and l.code = p.code_living_place 
and p.code_policy not in (select distinct b.code_policy 
          from bills b 
          where b.paid_out = '0') 

Ecco la SQL Fiddle dove si possono vedere i risultati.

MODIFICA: questa query funzionerà quando il cliente ha una politica pari a zero o zero (vale a dire una o zero case). La query richiede attenzione per> 1 casa/politica.

Answer 4

abbastanza sicuro che sia questo:

select c.ID, c.name 
from customers c 
where c.ID in (
    select lp.id 
    from policies p 
    join living_places lp on p.code_living_place = lp.code 
    join bills b on b.code_policy = p.code_policy 
    group by lp.id 
    having sum(b.paid_out = 1) = count(*)); 

restituisce 0 record con i dati che si hanno attualmente e se si modifica la banconota da un Luigi non ha pagato a pagamento allora apparirà nei risultati.

Here's a SQL Fiddle to play around with.

Answer 5

dispiace per il posto ripetuta, la risposta è stata:

SELECT x.name 
FROM 
(SELECT c.name, SUM(CASE WHEN b.paid_out THEN 0 ELSE 1 END) all_paid 
FROM customers c JOIN living_places l ON c.ID = l.ID 
JOIN policies p ON l.code = p.code_living_place 
JOIN bills b ON p.code_policy = b.code_policy 
GROUP BY c.name) x 
WHERE x.all_paid = 0; 

risposta da @ Davide Bachmann Jeppesen: Select a specific customer in MYSQL?