Numero chiuso gruppo

Question

Ho una tabella con 2 colonne di numeri interi. La prima colonna rappresenta l'indice iniziale e la seconda colonna rappresenta l'indice finale.

START END 
1  8 
9  13 
14 20 
20 25 
30 42 
42 49 
60 67 

Semplice Finora. Quello che vorrei fare è raggruppare tutti i record che seguono insieme:

START END 
1  25 
30 49 
60 67 

Un record può seguire avviando sullo stesso indice come il precedente dell'indice finale o con un margine di 1:

START END 
1  10 
10 20 

E

START END 
1  10 
11 20 

saranno entrambi risultato

START END 
1  20 

Utilizzo SQL Server 2008 R2.

Qualsiasi aiuto sarebbe grande

Answer 1

Questo funziona per il tuo esempio, fammi sapere se non funziona per altri dati

create table #Range 
(
    [Start] INT, 
    [End] INT 
) 

insert into #Range ([Start], [End]) Values (1, 8) 
insert into #Range ([Start], [End]) Values (9, 13) 
insert into #Range ([Start], [End]) Values (14, 20) 
insert into #Range ([Start], [End]) Values (20, 25) 
insert into #Range ([Start], [End]) Values (30, 42) 
insert into #Range ([Start], [End]) Values (42, 49) 
insert into #Range ([Start], [End]) Values (60, 67) 



;with RangeTable as 
(select 
    t1.[Start], 
    t1.[End], 
    row_number() over (order by t1.[Start]) as [Index] 
from 
    #Range t1 
where t1.Start not in (select 
         [End] 
       from 
        #Range 
        Union 
       select 
        [End] + 1 
       from 
        #Range 
       ) 
) 
select 
    t1.[Start], 
    case 
    when t2.[Start] is null then 
     (select max([End]) 
        from #Range) 
     else 
     (select max([End]) 
        from #Range 
        where t2.[Start] > [End]) 
end as [End]  
from 
    RangeTable t1 
left join 
    RangeTable t2 
on 
    t1.[Index] = t2.[Index]-1 

drop table #Range; 

Answer 2

modificato per includere un'altra versione e penso che sia un po 'più affidabile, e funziona anche con sovrapposizione gamme

CREATE TABLE #data (start_range INT, end_range INT) 
INSERT INTO #data VALUES (1,8) 
INSERT INTO #data VALUES (2,15) 
INSERT INTO #data VALUES (9,13) 
INSERT INTO #data VALUES (14,20) 
INSERT INTO #data VALUES (13,26) 
INSERT INTO #data VALUES (12,21) 
INSERT INTO #data VALUES (9,25) 
INSERT INTO #data VALUES (20,25) 
INSERT INTO #data VALUES (30,42) 
INSERT INTO #data VALUES (42,49) 
INSERT INTO #data VALUES (60,67) 

;with ranges as 
(
SELECT start_range as level 
,end_range as end_range 
,row_number() OVER (PARTITION BY (SELECT NULL) ORDER BY start_range) as row 
FROM #data 
UNION ALL 
SELECT 
level + 1 as level 
,end_range as end_range 
,row 
From ranges 
WHERE level < end_range 
) 
,ranges2 AS 
(
SELECT DISTINCT 
level 
FROM ranges 
) 
,ranges3 AS 
(
SELECT 
level 
,row_number() OVER (ORDER BY level) - level as grouping_group 
from ranges2 
) 
SELECT 
MIN(level) as start_number 
,MAX(level) as end_number 
FROM ranges3 
GROUP BY grouping_group 
ORDER BY start_number ASC 

---

Penso che questo dovrebbe funzionare - potrebbe non essere particolarmente efficace su set più grandi però ...

CREATE TABLE #data (start_range INT, end_range INT) 
INSERT INTO #data VALUES (1,8) 
INSERT INTO #data VALUES (2,15) 
INSERT INTO #data VALUES (9,13) 
INSERT INTO #data VALUES (14,20) 
INSERT INTO #data VALUES (21,25) 
INSERT INTO #data VALUES (30,42) 
INSERT INTO #data VALUES (42,49) 
INSERT INTO #data VALUES (60,67) 


;with overlaps as 
(
select * 
,end_range - start_range as range 
,row_number() OVER (PARTITION BY (SELECT NULL) ORDER BY start_range ASC) as line_number 
from #data 
) 
,overlaps2 AS 
(
SELECT 
O1.start_range 
,O1.end_range 
,O1.line_number 
,O1.range 
,O2.start_range as next_range 
,CASE WHEN O2.start_range - O1.end_range < 2 THEN 1 ELSE 0 END as overlap 
,O1.line_number - DENSE_RANK() OVER (PARTITION BY (CASE WHEN O2.start_range - O1.end_range < 2 THEN 1 ELSE 0 END) ORDER BY O1.line_number ASC) as overlap_group 
FROM overlaps O1 
LEFT OUTER JOIN overlaps O2 on O2.line_number = O1.line_number + 1 
) 
SELECT 
MIN(start_range) as range_start 
,MAX(end_range) as range_end 
,MAX(end_range) - MIN(start_range) as range_span 
FROM overlaps2 
GROUP BY overlap_group 

Answer 3

È possibile utilizzare un number table per risolvere questo problema. Fondamentalmente, prima espandi gli intervalli, quindi combina gli elementi successivi in ​​gruppi.

Ecco uno attuazione:

WITH data (START, [END]) AS (
    SELECT 1, 8 UNION ALL 
    SELECT 9, 13 UNION ALL 
    SELECT 14, 20 UNION ALL 
    SELECT 20, 25 UNION ALL 
    SELECT 30, 42 UNION ALL 
    SELECT 42, 49 UNION ALL 
    SELECT 60, 67 
), 
expanded AS (
    SELECT DISTINCT 
    N = d.START + v.number 
    FROM data d 
    INNER JOIN master..spt_values v ON v.number BETWEEN 0 AND d.[END] - d.START 
    WHERE v.type = 'P' 
), 
marked AS (
    SELECT 
    N, 
    SeqID = N - ROW_NUMBER() OVER (ORDER BY N) 
    FROM expanded 
) 
SELECT 
    START = MIN(N), 
    [END] = MAX(N) 
FROM marked 
GROUP BY SeqID 

Questa soluzione utilizza master..spt_values come una tabella numerica, per espandere le gamme iniziali. Ma se (tutto o parte di) tali intervalli possono comprendere più di 2048 (successivi) valori, è necessario definire e utilizzare la tabella dei numeri your own.