È necessario mask
:
sample['PR'] = sample['PR'].mask(sample['PR'] < 90, np.nan)
Un'altra soluzione con loc
e boolean indexing
:
sample.loc[sample['PR'] < 90, 'PR'] = np.nan
Esempio:
import pandas as pd
import numpy as np
sample = pd.DataFrame({'PR':[10,100,40] })
print (sample)
PR
0 10
1 100
2 40
sample['PR'] = sample['PR'].mask(sample['PR'] < 90, np.nan)
print (sample)
PR
0 NaN
1 100.0
2 NaN
sample.loc[sample['PR'] < 90, 'PR'] = np.nan
print (sample)
PR
0 NaN
1 100.0
2 NaN
EDIT:
Soluzione con apply
:
sample['PR'] = sample['PR'].apply(lambda x: np.nan if x < 90 else x)
Tempilen(df)=300k
:
sample = pd.concat([sample]*100000).reset_index(drop=True)
In [853]: %timeit sample['PR'].apply(lambda x: np.nan if x < 90 else x)
10 loops, best of 3: 102 ms per loop
In [854]: %timeit sample['PR'].mask(sample['PR'] < 90, np.nan)
The slowest run took 4.28 times longer than the fastest. This could mean that an intermediate result is being cached.
100 loops, best of 3: 3.71 ms per loop
magari provare il cambiamento 'NaN' a' np.nan' – jezrael
Non è necessario alcun funzione di fantasia. Assegnalo semplicemente: 'sample.PR [sample.PR <90] = np.nan' – ssm