Sto tentando di effettuare una semplice richiesta https utilizzando questa libreria https://github.com/scalaj/scalaj-http. La richiesta contiene alcuni dati JSON.SocketTimeoutException quando utilizzo la richiesta di Scalaj
Ecco quello che sto facendo:
val jsonHeaders = """{"jsonrpc": "2.0", "method": "someMethod", "params": {"dataIds":["12348" , "456"]}, "data2": "777"}"""
val result = Http.postData("https://someurl.com/json-rpc", jsonHeaders)
.header("content-type", "application/json")
.header("X-Application", "myCode")
.header("X-Authentication", "myCode2")
.option(HttpOptions.readTimeout(10000))
.asString
//.responseCode -- the same error
println(result)
E mi restituisce sempre un errore di timeout:
[error] (run-main) java.net.SocketTimeoutException: connect timed out
java.net.SocketTimeoutException: connect timed out
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.AbstractPlainSocketImpl.doConnect(Unknown Source)
at java.net.AbstractPlainSocketImpl.connectToAddress(Unknown Source)
at java.net.AbstractPlainSocketImpl.connect(Unknown Source)
at java.net.SocksSocketImpl.connect(Unknown Source)
at java.net.Socket.connect(Unknown Source)
at sun.security.ssl.SSLSocketImpl.connect(Unknown Source)
at sun.net.NetworkClient.doConnect(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.protocol.https.HttpsClient.<init>(Unknown Source)
at sun.net.www.protocol.https.HttpsClient.New(Unknown Source)
at sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.getNewHttpClient(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(Unknown Source)
at sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.connect(Unknown Source)
at sun.net.www.protocol.https.HttpsURLConnectionImpl.connect(Unknown Source)
at scalaj.http.Http$$anonfun$3.apply(Http.scala:263)
at scalaj.http.Http$$anonfun$3.apply(Http.scala:261)
at scalaj.http.Http$Request.process(Http.scala:102)
at scalaj.http.Http$Request.apply(Http.scala:90)
at scalaj.http.Http$Request.asString(Http.scala:133)
at Application$delayedInit$body.apply(Application.scala:27)
at scala.Function0$class.apply$mcV$sp(Function0.scala:40)
at scala.runtime.AbstractFunction0.apply$mcV$sp(AbstractFunction0.scala:12)
at scala.App$$anonfun$main$1.apply(App.scala:71)
at scala.App$$anonfun$main$1.apply(App.scala:71)
at scala.collection.immutable.List.foreach(List.scala:318)
at scala.collection.generic.TraversableForwarder$class.foreach(TraversableForwarder.scala:32)
at scala.App$class.main(App.scala:71)
at Application$.main(Application.scala:8)
at Application.main(Application.scala)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
[trace] Stack trace suppressed: run last compile:run for the full output.
java.lang.RuntimeException: Nonzero exit code: 1
at scala.sys.package$.error(package.scala:27)
Se lo faccio solo
val jsonHeaders = """{"version123": "12.0", "method": "someMethod", "params": {"dataIds": ["12348" , "456"]}, "data2": "777"}"""
val result = Http.postData("https://someurl.com/some-url2", jsonHeaders)
.header("content-type", "application/json")
.header("X-Application", "myCode")
.header("X-Application1234", "myCode2")
.option(HttpOptions.readTimeout(10000))
println(result)
restituisce
Request(POST,<function2>,<function1>,List(),List((X-Authentication,myCode2), (X-Application1234,myCode), (content-type,application/json)),List(<function1>, <function1>, <function1>),DIRECT)
Cosa faccio di sbagliato e c'è un altro modo semplice per inviare la richiesta https? Anche se coinvolge il framework spray
, sarebbe ok (non trovo alcun esempio di come farlo in spray
, però).
UPDATE:
Un esempio è stato preso da qui Doing HTTP request in Scala
Sembra che la tua seconda richiesta non fa alcuna richiesta reale - è solo costruisce richiesta oggetto, che poi ottenere innescato da 'asString'. Sei sicuro che la richiesta possa essere soddisfatta entro il timeout specificato (ad es. Hai provato a fare lo stesso con arricciatura). –
@ om-nom-nom Posso commentare il timeout e nulla verrà modificato. –
@ om-nom-nom guarda il mio aggiornamento. Posso anche fare questa richiesta in Python e funzionerà bene. –